Chemistry, asked by abhinay4150, 1 month ago

. Decomposition of 25.0 ml hydrogen peroxide produces 50.0 ml of oxygen gas in 137 second. The rate of formation of O2 in ml/min is:
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Answered by sateeshhtp
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Answer:

Then 137 s = 137/60 = 2.28 min. If 50 ml of oxygen is produced in 2.28 min. Then rate of formation of oxygen would be : 50 ml / 2.28 min. = 21.93 ml/min

Explanation:

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