Question

Decomposition of N2O5 is first order reaction, t1/2 of the reaction n2o5 gives 2NO2 + 1/2 O2 is 2.4 hr at STP. Starting with 10.8gm of N2O5, how mush oxygen will be obtainedafter a period of 9.6hr

Answer 1

0.07 L oxygen will be obtained after a period of 9.6 hr.

Explanation:

Consider the given data

At STP condition the time will be 2.4 hr

weight of N2O5=10.8 gm

Half lift will be $\frac{T_{1} }{2} =2.4$=ln2/K

K=ln2/2.4

At the time period T=9.6

K=ln(0.1/N)/9.6=ln2/9.6

By solving the above equations we get

N=0.1/16

Number of liters of O2=N*22.4/2=0.07L

Learn more

Properties of N2O5

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Answer 2

Answer:

1.05L

Explanation:

hope it helps!

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