Question

Decrease in s-character in hybridization decreases the bond angle:sp 180°,sp2 120°, sp3 109°28'. In H2O molecule the bond angle is 104.5°. the s- character in hybridization of O-atom in H2O is likely to be :
(a) more than 50%. (b) 33-50%
(c) 25-33%
(d) less than 25%​

Answer 1

Answer:

C

25% - 33%

Explanation:

Answer 2

The s- character in the hybridization of O-atom in H₂O is likely to be less than 25 percent. (Option D)

• We concentrate on the oxygen atom during the creation of a water molecule.
• The oxygen atom is sp³ hybridized during H₂O hybridization.
• The sp³ hybridized orbital contains 25% s- character and 75% p- character.
• The more the s-character of a connection, the stronger and shorter the relationship.
• As a result, the bond length decreases as the s character increases.
• Decrease in s-character in hybridization decreases the bond angle.
• Thus, the s-character in the hybridization of O-atom in H₂O is likely to be less than 25 percent.