Chemistry, asked by archie44, 10 months ago

Decreasing order (first having highest and then
others following it) of mass of pure NaOH in
each of the aqueous solution :-
(1) 50 g of 40% (w/W) NaOH
(ii) 50 mL of 50% (w/V) NaOH (doln. = 1.2 g/mL]
(iii) 50 g of 15 M NaOH [dsoln. = 1 g/mL]
(1) i, ii, iii
(2) iii, ii, i
(3) ii, iii, i
(4) ii, i, iii​

Answers

Answered by Anonymous
2

Answer:

Decreasing order (first having highest and then

others following it) of mass of pure NaOH in

each of the aqueous solution :-

(1) 50 g of 40% (w/W) NaOH

(ii) 50 mL of 50% (w/V) NaOH (doln. = 1.2 g/mL]

(iii) 50 g of 15 M NaOH [dsoln. = 1 g/mL]

(1) i, ii, iii

(2) iii, ii, i

(3) ii, iii, i ✔️✔️

(4) ii, i, iii

→ Hope it will help you ❣️❣️

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Answered by AbdJr10
2

Answer:

3. is the correct answer

Explanation:

hope the answer will help you

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