Decreasing order of de-Broglie's wavelength with same velocity
Answers
Answered by
0
Explanation:
Now, since all the particles are moving with same velocity, the particle with least mass will have maximum de-Broglie wavelength. Out of the given four particles (proton, α -particles, i.e. He nucleus and β-particles. i.e. electrons) β-particles has the lowest mass and therefore it has maximum wavelength.
Similar questions