Chemistry, asked by vasireddynavya8, 2 months ago

Decreasing order of de-Broglie's wavelength with same velocity​

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Answered by Anonymous
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Explanation:

Now, since all the particles are moving with same velocity, the particle with least mass will have maximum de-Broglie wavelength. Out of the given four particles (proton, α -particles, i.e. He nucleus and β-particles. i.e. electrons) β-particles has the lowest mass and therefore it has maximum wavelength.

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