decribe an activity to find the area of a rose petal ??
Answers
Explanation:
A sketch is useful here, but the only important observation is that r=0 when θ=0, and again at π3. These are your limits for one petal.
Since the area of a polar curve between the rays θ=a and θ=b is given by ∫ba12r2dθ, we have
A=∫π/3012sin2(3θ)dθ=12∫π/301−cos(6θ)2dθ
=14[θ−sin(6θ)2]π/30=14(π3−12sin(6π3))=π12
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Mar 12 '13 at 20:02
preferred_anon
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m just confused how we notice that r=0..etc etc plz tell me a simple and unique way to solve such problems like roses ,polar quad etc etc ... – user116518 Dec 18 '13 at 2:48
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Alternately we could compute 13∫π012sin2(3θ)dθ. – tc1729 Dec 18 '13 at 3:09
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Answer:
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