Question

deduce an expression for electric potential on axial position of an electric dipole​

Answer 1

Answer:

Let P be an axial point at distance r from the center of the dipole. Electric potential at point P is given as

V=V

1

+V

2

V

1

and V

2

are the potentials at point P due to charges +q and –q respectively

V=

4πε

0

1

(

r−2a

q

+(

r+2a

−q

))

V=

4πε

0

1

(

(r

2

−4a

2

)

4a

)

V=

4πε

0

1

(

(r

2

−4a

2

)

2P

)

Hence, the electric potential is

4πε

0

1

(

(r

2

−4a

2

)

2P

)

Explanation:

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