Physics, asked by ritikamande7218, 1 year ago

Deduce an expression for pressure exerted by a liquid column of height H

Answers

Answered by RikCena
1
suppose a vessel of cross section A is completely submerged in water and it places itself at the bottom of the vessel containing water.

F = m × g
= d × v × g
= d × h×A × g

P = F/A
= d × h×A×g/A
= hdg
Answered by namirata1
0

Answer:

The expression for the pressure is hpg

Let the liquid column of area be = A (Given)

Let the height of the container be = h (Given)

Let the pressure at upper and lower columb of the liquid be = P1 and P2

Volume V = A h,

Where its mass when density of the liquid is ρ is represented by,mass = m =Ah

ρ and the weight acting vertically downwards is represented as W = Ahρg

Net pressure acting downwards = P1 + w/a

= P1 + Ahpg/A

= P1 + hpg

Net pressure acting upwards = P2

P2 = P1 + hpg or P2 - P1 = hpg

Therefore, the pressure exrted by the liquid column on the bottom of the container is represented by hρg.

Explanation:

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