Question

Deduce an expression for the intensity of sound

Answer 1

Explanation:

Sound intensity, amount of energy flowing per unit time through a unit area that is perpendicular to the direction in which the sound waves are travelling.

The intensity of a sound wave is related to its amplitude squared by the following relationship: I=(Δp)22ρvw I = ( Δ p ) 2 2 ρ v w . Here Δp is the pressure variation or pressure amplitude (half the difference between the maximum and minimum pressure in the sound wave) in units of pascals (Pa) or N/m2.

Sound intensity, also known as acoustic intensity, is defined as the power carried by sound waves per unit area in a direction perpendicular to that area. The SI unit of intensity, which includes sound intensity, is the watt per square meter

(W/m²). One application is the noise measurement of sound intensity in the air at a listener's location as a sound energy quantity.

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Answer 2

CONCEPT:

Sound Intensity: It is also known as acoustic intensity.

It is the power carried by sound waves per unit area in a direction perpendicular to that area.

The sound intensity level is just a logarithmic expression of sound intensity relative to a reference intensity.