deduce an expression for the pressure at a depth inside a liquid
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pressure, P=(M1L0T1)
height, h=L3
solve using above dimensional formula
height, h=L3
solve using above dimensional formula
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Let us consider a container which contains a liquid of density d.
consider a cylindrical column of height h from the surface of liquid of cross section area A.
the volume of liquid column
V=Ax h
mass = density x volume
m= Axhxd
weight w= mxg
w=mg
= Axhxdxg
there are three forces acting on water column.
1. weight, vertically down.
2. force on top surface due to atmospheric pressure ( P°A), acting vertically Down.
3. Force on bottom surface if column due to static pressure of liquid ( PA), acting vertically up
from Newton's law
PA= P° A +w
PA = P° A + hdgA
P= P° + hdg
note : P° read it as p not.
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