Physics, asked by dareppamanturmantur, 1 month ago

deduce expression for elastic potential and isolated change​

Answers

Answered by aashibanushkae
0

Answer:

Consider the electric potential due to a point charge q, As we move from point A, at distance rA from the charge q, to point B, at distance rB from the charge q, the change in electric potential is

ΔV

BA

=V

B

−V

A

=−∫

A

B

E.ds

E.ds=[k

r

2

q

]

r

^

.ds

r

^

.ds=dr

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