Question

Deduce pH+pOH=14.Answer the given question.

Answer 1

Hey there!

----------

In pure water 25° (298 K)

$[H^{+}] = 1.0 \times 10^{-7}$ mol $L^{-1}$

㏒$[H^{+}] =$ ㏒($10^{-7}]$

and, pH = -㏒$[H^{+}] = -(-7)$

pH = 7

Since, in pur water 25°C (298 K)

$[OH^{-}] = 1.0 \times 10^{-7}$ mol $L^{-1}$

Also, pOH =7

Since, Kw = $1.0 \times 10^{-14}$

pKw = 14

The realtionship between pKw, pH and pOH is :

w = pH + pOH at 25°C (298 K)

∴ 14 = pH + pOH