Question

Deduce the capacitance of parallel plate capacitor.Three capacitors of 2µF,3µF and 5µF are connected in parallel with a battery of 20 volt.Find the equivalent capacitance and charge on each capacitor.

plz ans fast​

Answer 1

Answer:

eq capacitance=c1+c2+c3

=2+3+5=10μF

v=20v

c=q/v=10=q/20

q=200C

Explanation:

Answer 2

Answer:

Given:-

Capacitors = 2µF, 3µF, 5µF

Voltage = 20V

So we know that they are connected in parallel

C parallel = C1+C2+C3

= 2+3+5 = 10µF

Charge on each capacitor

By applying Q = C×V

= 2×20

= 40C.

For 2nd Capacitor,

= 3×20

= 60C.

For 3rd Capacitor,

= 5×20

= 100C.

Total charge,

= 10×20

= 200C.