Question

Deduce the dimensional formula of the Gravitational Constant 'G'? Find its dimensional formula of G?
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Answer 1

As we know,

F=Gr^2/m1xm2

So, G=Fr^2/m1xm2

G=[ML^2T^-2]/[M^2]

G=[M^-1L^3T^-2]

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Answer 2

Answer:

According to the Newton 's law of gravitation,

${\huge{\red{F = Gm1m2 /r^2}}}$

.°. [G] = [F][r²] / [m1][m2]

[G] = [MLT^-2][L²] / M²

[G] = [M^-1 L^3 T^-2] Answer

${\blue{\boxed{So,\:the\:dimensional \:formula\: of\: G\: is \:</p><p>[G] = [M^-1 L^3 T^-2]}}}$