deduce the expression for the speed of a compressional wave through an extended solid
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pulse (compression) travel in the fluid-filled tube. we observed that, after elementary time (Δt) net force =forward force - backward force
F = pA -(p + Δp)A = -pA---------(1)
now, we know,
mass = volume × density
m = V × ρ
for elementary mass Δm = ΔV × ρ
= A.Δx × ρ
= Av.Δt × ρ
here, the air occupies a volume V = AvΔt outside the pulse is compressed by an amount of ΔV = AΔv.Δt as it enters in the pulse.
so, ΔV/V = Δv/v---------------(2)
now, F = Δm.a = Av.Δt × ρ .Δv/Δt = Aρv.Δv--------(3)
from (1) (2) and (3)
pv² = -Δp/[ΔV/V] = bulk modulus = B
v= √(B/ρ
F = pA -(p + Δp)A = -pA---------(1)
now, we know,
mass = volume × density
m = V × ρ
for elementary mass Δm = ΔV × ρ
= A.Δx × ρ
= Av.Δt × ρ
here, the air occupies a volume V = AvΔt outside the pulse is compressed by an amount of ΔV = AΔv.Δt as it enters in the pulse.
so, ΔV/V = Δv/v---------------(2)
now, F = Δm.a = Av.Δt × ρ .Δv/Δt = Aρv.Δv--------(3)
from (1) (2) and (3)
pv² = -Δp/[ΔV/V] = bulk modulus = B
v= √(B/ρ
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