Deduce the following equation of motion:
V²=U²+2as
S=ut+½at²
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Answer:
First of all you have to know the other two equations of motions :
V=u+at
S=ut+1\2at2
Now the derivation:
From the first equation we have :
at=v−u
t=v−u\a
Now putting the value of t in the second equation of motion:
s=u(v−u\a)+1\2a(v−u\a)2
s=uv−u2\a+a(v2+u2–2vu)\2a2
s=uv−u2\a+(v2+u2+2vu)\2a
s=(2uv−2u2+v2+u2–2vu)\2a
2as=v2−u2
v2=u2+2as
So here it is.. hope it helps :)
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