Question

Deduce the molecular mass of given compounds

Atomic masses > H(1), O(16), N(14), C(12), K(39), S(32) Ca( 40), Na(23), CI(35.5), Mg(24), Al(27)

Molecular formulae → NaCl, MgCl,, KNO,, H,02, AICI,, Ca(OH),, MgO, H,SO HNO, NaOH​

Answer 1

Answer:

Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water

5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g

LHS RHS

11.3 g = 11.3 g

(Mass of reactant) (Mass of product)

This shows, that during a chemical reaction mass of reactact = mass of produce