Question

deduce the number of molecules in 90 gram of water (Atomic mass :H - 1 ,O - 16 )​

Answer 1

Answer:

m = 90 g

M = 18 g

Avogadro # = 6.022*10^23

N = ?

90/18 = N/6.022*10^23

5 = N/6.022*10^23

N = 5*6.022*10^23

  = 30.11 * 10^23

  = 3.011 * 10^24

Answer 2

Answer:

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