Question

Deduce the number of molecules of
the following compounds in the given
quantities.
32g oxygen, 90g water, 8.8g carbon di
oxide, 7.1g chlorine.

for oxygen
mass = 32 g
molar mass = 32 g
no of molecular = mass/molar mass
Avogodro's number
no of molecular = 32/32×6.022×10^23
6.022×10^23
for water
mass = 90 g
molar mass = 18 g
no of molecular = 90 / 18 ×6.022×10^23
= 5 × 6.022×10^23
= 3.011×10^23 molecular
for carbon dioxide
mass = 8.8 g
molar mass = 44 g
n of molecular = 8.8/44×6.022×20^23
1.2044×10^23 molecular
for clorin
mass = 7.19
molar mass = 719
no of molecular =7.1/71×6.022×10^23
= 6.022×10^23 molecular


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Answer 1

Answer:

don't know if you have any idea tell me also

Answer 2

Answer:

your answer

Explanation:

Deduce the number of molecules of the following compounds in the given quantities. (32g oxygen, 90g water, 8.8g carbon dioxide, 7.1g chlorine). There are 6.022 x 1023 molecules in 1 mol. Thus, no of molecules = 0.1 x 6.022 x 1023= 0.6022 x 1023.