Deduce the number of molecules present in 90 gm of water.
(molecular mass of water = 18 amu)
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Answered by
8
Answer:
30.11×10^23
Explanation:
No of molecules = Given No. / Molar mass × Avogadro number
". = 90 / 18 × 6.022× 10^23
= 30.11 × 10^23
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Answer:
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