Deduce the value of k, if y + 3 is a factor of 32 + ky + 6 pythagorean triplet whose one member is 18... Please help... I'm not getting any decent answers
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If we take m2 + 1 = 18,
m2 = 17
The value of m will not be an integer.
If we take m2 − 1 = 18, then m2 = 19
Again the value of m is not an integer.
Let 2m =18
m = 9
Thus, m2 − 1 = 81 − 1 = 80 and m2 + 1 = 81 + 1 = 82
the Pythagorean triplet is 18, 80, and 82.
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m2 = 17
The value of m will not be an integer.
If we take m2 − 1 = 18, then m2 = 19
Again the value of m is not an integer.
Let 2m =18
m = 9
Thus, m2 − 1 = 81 − 1 = 80 and m2 + 1 = 81 + 1 = 82
the Pythagorean triplet is 18, 80, and 82.
hope this will help you
Mark me the brainliest and be safe in this lockdown period
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