Question

deduce x minus 1 whole square
$(x - 1) {?}^{2}$
​

Answer 1

Step-by-step explanation:

( x - 1 )²

it is in the form of ( a - b )² = a² - 2ab + b²

= (x)² - 2(x)(1) + (1)²

= x² - 2x + 1

Answer 2

Answer:

$( {a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ \\ \\ = > {(x - 1)}^{2} = {x}^{2} - 2(x)(1)+ {1}^{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} - 2x + 1$