Deepa age of three times that of her brother Devan after two years Deepa age would be two times of devan how old are they now.
Answers
Answer:
Devan's age is 2 and Deepa's age is 6
Answer:
Their present ages:-
Devan's age = 4-2 = 2 years
Deepa's age = 8-2 = 6 years
After 2 years:
Devan's age will be = x+2 = 2+2 = 4 years
Deepa's age will be = 3x+2 = 6+2 = 8 years
Step-by-step explanation:
let, Devan's age be = x
therefore, Deepa's age = 3 times of Devan's age
= 3×x
= 3x
Now after 2 years,
Devan's age = x+2
Deepa's age = 3x+2
According to the Problem ( A.T.P) :
=> 2(x+2) = 3x+2 [ as Deepa's age is two times of her
brother's age ]
=> 2x+4 = 3x+2
=> +2x-3x = +2-4
=> -1x = -2
=> x = -2/-1
=> x = 2 [ as Minus(-) sign will cancel in
Numerator and Denominator ]
therefore,
After 2 years:
Devan's age will be = x+2 = 2+2 = 4 years
Deepa's age will be = 3x+2 = 6+2 = 8 years
{ Deepa's age is 8 years which is twice the age of her brother, as given already in the question }
Their present ages:-
Devan's age = 4-2 = 2 years
Deepa's age = 8-2 = 6 years
Hope the Answer is Correct.