deepa deposited Rs 1000 in first month Rs 1450 in second month and Rs 1900 in third month and so on up-to 5 years in a bank find the total amount that deepa deposited at the end of the 5 years
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Given, a = 1000
d = 1450 - 1000
Therefore , d = 450
Moreover , n = 5
Sn = n/2 [ 2a + ( n - 1 )d ]
S5 = 5/2 [ 2(1000) + (5 - 1 ) 450 ]
S5 = 5/2 [ 2000 + 4 × 450 ]
S5 = 5/2 [ 2000 + 1800 ]
S5 = 5/2 [ 3800 ]
S5 = 5 × 1900
S5 = 9500
Therefore, the total amount of money that deepa deposited at 5 years is Rs 9500.
d = 1450 - 1000
Therefore , d = 450
Moreover , n = 5
Sn = n/2 [ 2a + ( n - 1 )d ]
S5 = 5/2 [ 2(1000) + (5 - 1 ) 450 ]
S5 = 5/2 [ 2000 + 4 × 450 ]
S5 = 5/2 [ 2000 + 1800 ]
S5 = 5/2 [ 3800 ]
S5 = 5 × 1900
S5 = 9500
Therefore, the total amount of money that deepa deposited at 5 years is Rs 9500.
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