Math, asked by sneha264146, 7 months ago

deepa runs an industry in a shed which is in the shape of a cuboid surmounted by a half cylinder. the base of the shed is of dimensions 7m multiply 15m and the height of the cuboid portion is8 m. 1 no find the vol me of air that the shed can hold. 2no suppose the machinery in the shed occupies a total space of 300 m Square and there are 20 workers, each of whom occupy about 0.08 m cube space on an average. then, how much air is in the shed? 3 no find the internal surface area of the shed, exchange the floor.​

Answers

Answered by amitnrw
10

Given  : deepa runs an industry in a shed which is in the shape of a cuboid surmounted by a half cylinder. the base of the shed is of dimensions 7 m multiply 15 m and the height of the cuboid portion is 8 m

To Find : 1.   find the vol me of air that the shed can hold.

2. suppose the machinery in the shed occupies a total space of 300 m³  there are 20 workers, each of whom occupy about 0.08 m³ space on an average. then, how much air is in the shed?

3. find the internal surface area of the shed, excluding  the floor.​

Solution:

Volume of Cuboid  = length * breadth * Height

7 * 15  * 8  

= 840 m²  

Volume of half cylinder = (1/2) πr²h

Taking 7 as Diameter  , r = 3.5

h  = 15

π = 22/7

= (1/2)(22/7)(7/2)² ( 15)

= 77 * 15/4

= 288.75 m²  

Volume of air that the shed can hold  = 840 + 288.75

= 1128.75 m²

machinery in the shed occupies a total space of 300m³

20 workers occupy = 20 *0.08  = 1.6 m³

air  in shed =  1,128.75 - 300 - 1.6   =  827.15‬ m³

internal surface area of the shed excluding floor

= 2 * (15 + 7) * 8  +  (1/2)2πrh

= 352  +  (22/7)(7/2)* 15

= 352 + 165

= 517 m²

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