Question

Deepa's mother is four years more than three times as old as Deepa is now. 6 years from now she will be 8 years more than twice as old as Deepa will be then how old is each of them now​

Answer 1

Answer:

Deepa and her mother's present age is 10 years and 34 years respectively.

Step-by-step explanation:

Let Deepa and her mother's present age be x and y respectively.

Given,

y = 3x + 4 ---- Eq 1

y + 6 = 2(x + 6) + 8 ----- Eq 2

Substituting Eq 1 in Eq 2,

(3x + 4) + 6 = 2(x + 6) + 8

=> 3x + 4 + 6 = 2x + 12 + 8

=> 3x - 2x = 12 + 8 - 4 - 6

=> x = 10

Substituting x = 10 in Eq 1,

y = 3(10) + 4

=> 30 + 4 = 34

Deepa and her mother's present age is 10 years and 34 years respectively.

Answer 2

Answer:

this is the right answer.

hipe it helps