Math, asked by Areeba3278, 1 year ago

deepak and amir bought a cake. deepak ate 2 by 5 of cake. amir ate 3 by 10 of it who ate more and how much more

Answers

Answered by amitnrw
27

Answer:

Deepak ate 1/10 more

Step-by-step explanation:

Deepak ate 2/5 = 4/10

Aamir ate 3/10

4 is more than 3

So deepak ate more

4/10-3/10 = 1/10

Answered by sharonr
4

Deepak has eaten more cake

Deepak has eaten more by \frac{1}{10} of the cake

Solution:

Given that,

Deepak and Amir bought a cake

Deepak ate 2 by 5 of cake

Find the quantity of cake eaten by Deepak

Deepak = \frac{2}{5}

Convert to decimal form

Deepak = 0.4

Amir ate 3 by 10 of it

Find the quantity of cake eaten by Amir

Amir = \frac{3}{10}

Convert to decimal form

Amir = 0.3

Who ate more and how much more ?

By comparing we can observe,

0.4 > 0.3

Thus, Deepak has eaten more cake

0.4 - 0.3 = 0.1 = \frac{1}{10}

Thus, Deepak has eaten \frac{1}{10} of the cake more than Amir

Learn more about this topic

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