Question

Deepak bought a basket of mangoes containing 250 mangoes 12 percent of these were found to be rotten.Of the remaining,10 percent got crushed .How many were in good condition ​

Answer 1

Out of 250 mangoes, 25% were rotten.

Therefore, remaining mangoes

= 250-(250×25/100)

= 250-30

= 220

Now out of 220 mangoes, 10% got crushed.

Therefore, remaining mangoes

$= 220-(220×10/100)= 220-22= 198$

= 220-(220×10/100)

= 220-22

= 198

Hence, 198 mangoes were in good condition.

Answer 2

Answer:

195 mangoes were left

Step-by-step explanation:

250/100 per

=2.5

1per=2.5mangoes

then

12per (rotten mangoes)+10per(crushed)

=22per

1per=2.5mangoes

then

22 per ×2.5= 55

actuall mangoes =250

then the mangoes in good condition are =250-55=195