Question

deepak is 5 years old than deep. five year ago deepak was twice as old as deep was than. find their present ages.

Answer 1

HEY MATE HERE IS YOUR ANSWER
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➡️ Let the age of deep = x

➡️ Age of deepak = 5 years

✔️ After 5 years
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➡️ Age of deep = x + 5

➡️ Age of deepak = 5x + 5


According to Question
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➡️ x + 5 = 5x + 5

➡️ 4x = 0

➡️ x = 4

Now age of deep = 4 years

Age of deepak = 5(x) = 5 × 4 = 20 years

Answer 2

Their present ages are 10 and 15 years respectively.

Given:

Deepak is 5 years old than deep. five years ago Deepak was twice as old as deep was then.

To Find:

Their present ages.

Solution:

To find their present ages. we will follow the following steps:

Let the present age of deep = x

According to the question:

Deepak's present age = x + 5

Five years ago deep's age = x - 5

Five years ago Deepak's age will be = 2 × deeps age 5 years ago.

So,

Five years ago Deepak's age will be = 2 × (x - 5).

But Deepak's age 5 years ago can be written = Deepak's present age - 5 = x +5 - 5 = x

Now,

Equate Deepak's age in the two equations 5 years ago.

x = 2 × (x - 5).

x = 2x - 10

2x - x = 10

x = 10

So,

Deep's present age = 10 years

Deepak's present age = x + 5 = 15 years

Henceforth, their present ages are 10 and 15 years respectively.

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