Question

Deepak is twice as his brother vikash.if the different of their ages be 11 years find their present ages

Answer 1

Answer:

Present age of Vikash is 11 years and present age of Deepak is 22 years.

Step-by-step explanation:

It is given that Deepak is twice as his brother Vikash and the different of their ages be 11 years.

Let the present age of Vikash be a years and present age of Deepak be 2a years, Deepak's age is twice of Vikash's age and twice of a years is 2a years.

According to the question : -

⇒  Difference between Deepak's age and Vikash's age = 11 years

= >  2a years - a years = 11 years

= >  a years = 11 years

Hence,

Present age of Vikash is 11 years and present age of Deepak is 2( 11 ) years = 22 years

Answer 2

Answer:

Step-by-step explanation:

let age of deepak be x

age of vikash be y

so, x=2y

x-2y=0....(1)

x-y=11...(2) (subtract equation 1 and 2)

_________

0-y= -11

y=11

therefore, x=2(11)

x=22

so,

age of deepak is 22 years

age of vikash is 11 years