Question

Deepak is twice as old as his brother vikas. if the difference of their ages be 11 years, find their present ages.

Answer 1

Answer:

The ages of Vikas and Deepak are 11 and 22 years respectively.

Step-by-step explanation:

Let the age of Deepak be 'x' Vivek be 'y'

Now using the variables we can form an equation from the given pieces of information. Therefore,

  x = 2y → (1)

It is also given that their age difference is 11 years. That is,

  x - y = 11 → (2)

Now substitute the equation (1) in (2) then we get as follows,

 2y - y = 11

    y = 11

Now put the value of 'y' in equation (1) to find the value 'x'. Therefore,

  x = 2 × 11

  x = 22

Hence the ages of Vikas and Deepak are 11 and 22 years respectively.

     

   

Answer 2

Answer:

Deepak is 11 years old, brother is 22 years old

Step-by-step explanation:

D : B

2 : 1

2u - 1u = 11

       1u = 11

      2u = 11 x 2

            = 22