Math, asked by siya248966, 8 days ago

# Deepak is twice as old as his brother Vikas. If the difference of their ages be 11 years, fintheir present ages,​

## Answers

Answered by Anonymous
2

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Answered by EnchantedBoy
8

## Answer:-

Given:-

• Deepak is twice as old as his brother Vikas
• Difference of their ages is 11 years

To find:-

• their present ages

Solution:-

Let age of Vikas be x

Given,

Age of Deepak = age of Vikas + 11

( Here age of Vikas is x )

Age of Deepak = x + 11--------( 1 )

also, age of Deepak = 2 ( age of Vikas )

Age of Deepak = 2 ( x )--------( 2 )

Here, from equation ( 1 ) and ( 2 )

⇒x + 11 = 2x

⇒2x - x = 11

⇒x = 11

Here, we got the age of Vikas is 11 years

( Here, Deepak is twice bigger than Vikas)

So, age of Deepak = 11 + 11 ⇒ 22 years

Age of Deepak = 22 years

Age of Vikas = 11 years

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