Question

Deepak is twice as old as his brother Vikash.If the difference of their age be 11 years,find their present age.

Answer 1

Let Vikash be x years old.

Deepak is twice as old

⇒ Deepak = 2x

The difference in their age is 11 years:

2x - x = 11

x = 11 years

Find their present age:

Vikash = x = 11 years old

Deepak = 2x = 2(11) = 22 years old

Answer: Vikash is 11 years old and Deepak is 22 years old

Answer 2

$\text{Hey there!}\\\\\text{Let the present age of Vikas be x years.}\\\text{Then present age of Deepak = 2x }\\ATQ,\\2x - x = 11\\{\boxed{{\bold{x = 11}}}$

$\\\\\text{\large{Age of Vikas} } = \text{\large{x}} = \huge{11}\\\\\text{\large{Age of Deepak = 2x = 2 * 11 = 22}}$