Math, asked by IrabanBhattacharya14, 4 months ago

Deepak is twice as old as his brother Vilas. If the difference of their ages be 11 years, find
their present agea​

Answers

Answered by riyakaramchandani05
1

Let the Vikas age be x.

Then the age of Deepak will be 2x.

Given that difference in their ages be 11 years.

2x−x=11

x=11.

The age of Deepak will be 2×11=22years.

Answered by Anonymous
36

Answer:

Answer:

Age of Vikas is 11 years

Age of Deepak is 22 years.

Given :-

➤ The difference of their age is 11

Have to find :-

➤ What's the present ages of Deepak and Vikas

Solution :-

So , we firstly consider Vikas age as x years .

Then become Deepak age will be 2x years

Now ,

As per the question :-

⇒ 2x - x = 11

⇒ x = 11

Now , we got the value of x from this :-

Therefore ,

Substituting the values :-

Hence ,

The age of Vikas = x = 11 years old.

Age of Deepak = 2x = 2 * 11 = 22 years old .

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