Question

Deepak’s present age is one-third his mother’s present age. If the mother’s age was five times his age 6 years ago, what are their present ages?

Answer 1

Answer:

deepak age=10

his mother a=30

Step-by-step explanation:

his mothers = 6×5=30

deepak age= 30×1/3=10

Answer 2

Answer:

Let present age of mother = x years

Deepak’s present age =x3years

6 years ago, mother’s age = (x – 6) years

Deepak’s age =(x3–6) years

According to the problem, 6 years ago, mother’s age is 5 times Deepak age.

i.e., (x – 6) =5×(x3–6)

x–5x3=–30+6

3x–5x3=–24

–2x3=–24

2x=24×3

x=722=36

Therefore, present age of mother = 36 years and

Present age of Deepak =x3=363=12years