Question

Deepan suffered a loss of 15% on a mobile which he sold at the price of ₹15,300. At what price did he purchase that mobile?​

Answer 1

$\huge {\red {\mathfrak {Question:-}}}$

• Deepan suffered a loss of 15% on a mobile which he sold at the price of Rs 15,300. At what price did he purchase that mobile?

$\huge {\pink {\mathfrak {Solution:-}}}$

$\underline{\bold {Given :}}$

• Loss%=15%
• SP=Rs 15,300

$\underline{\bold {To\:Find:}}$

• The price at which deepan purchased that mobile.(CP)

Now we are going to find CP :

$\boxed {\blue {SP=CP-Loss}}$

Let the CP be Rs x.

Atq,

$\implies SP=CP-Loss \\ \\ \implies 15300 = x - 15\% \: of \: x \\ \\ \implies 15300 = x - x \times \frac{15}{100} \\ \\ \implies 15300 = x - \frac{3x}{20} \\ \\ \implies 15300 = \frac{20x - 3x}{20} \\ \\ \implies 15300 = \frac{17x}{20} \\ \\ \implies 15300 \times 20= 17x \\ \\ \implies \frac{15300 \times 20}{17} = x \\ \\ \implies 900 \times 20 = x \\ \\ \implies 18000 = x \\ \\\implies x = 18000$

$\green {\tt {\therefore{The\: price\: at \:which \:deepan \:purchased \:that\: mobile\:is\:Rs\:18,000.}}}$

Answer 2

Step-by-step explanation:

Given:

loss = 15 %

Selling Price = ₹ 15,300

To find:

The price at which deepan purchased that

mobile. (Cost Price)

Solution:

let, The cost price be ₹ x .

According to question,

$</p><p>x - 15 \% \: \: o f x = 15300 \\ \\ x - 15 \times \frac{x}{100} = 15300 \\ \\ x - \frac{15x}{100} = 15300 \\ \\ \frac{100x - 15x}{100} = 15300 \\ \\ \frac{85x}{100} = 15300 \\ \\ \frac{ 17x}{20} = 15300 \\ \\ \frac{x}{20} = 900 \\ \\ x = 18000$

Hence, the required answer is ₹ 18000.

$\mathbff{ Some \: important \:formula\: of\: Profit \:and\: Loss \: }$

Cost Price = Sell Price + Loss

Cost Price = Sell Price - Profit

$Profit \: Percentage = \dfrac{Total \:Profit}{ Cost\: Price} \times 100</p><p>\\ \\</p><p>Loss \: Percentage = \dfrac{Total\: Loss}{ Cost \: Price} \times 100$