Math, asked by laki4355, 1 year ago

Deepik is twice as old as his brother Vikas. If the difference of their age be 11 years, find their present age.

Answers

Answered by sid8126
1
Let x = Vikas' age

Deepak is twice as old as his brother Vikas
Deepak's age = 2x

The difference between their ages is 11 years
Deepak's age = 11 + x

2x = 11 + x
2x - x = 11
x = 11

Vikas' age = 11
Deepak's age = 22

mark me as brainliest
Answered by Anonymous
1
\large\boxed{Ahem!! Hey Your Answer}

let the age of Deepik be 'X' years
and the age of his brother be 'Y' years

A/Q
x = 2Y ---------(1)

X-Y = 11 -------------( 2)

substituting the value of X in eqn 2
2 y - Y = 11

\small\boxed<br />{Y = 11 years}

and the value of x is

X = 2y

\small\boxed<br />{X = 22years}

\color{red}{Age Of Deepik is 22years}

\color{red}{Age Of Deepik's brother is 11 years}

mairazainab: NICE ANSWER ~_`
mairazainab: >>_<
mairazainab: #_#
mairazainab: Helllloooo
Similar questions