Question

Deepika buys two bangle set for a total cost of rs. 600. By selling one bangle set for 4/5 of its cost and the other for 5/4 of its cost, she makes a profit of rs. 96 on the whole transaction. The cost of the lower priced bangle set is?

Answer 1

Answer:

Step-by-step explanation:

total cost =₹600

SELLING PRICE OF 1ST BANGLE SET=  600 *4/5

                                                                 = ₹480/

SELLING PRICE OF 2ND BANGLE SET = 600*5/4

                                                                 = ₹750

                                                                                   =

Answer 2

The cost of the lower priced bangle set is Rs 120

Solution:

Total cost of two bangle set = Rs 600

Let the cost price of 1st bangle set = x

Let the cost price of 2nd bangle set = 600 - x

By selling one bangle set for 4/5 of its cost

$Selling\ Price\ of\ first\ set = \frac{4}{5}x$

And the other for 5/4 of its cost

$Selling\ Price\ of\ second\ set = \frac{5}{4} \times 600- x$

She makes a profit of rs. 96 on the whole transaction

Profit = 96

We know that,

Profit = SP - CP

$96=\frac{4x}{5} +\frac{5}{4} \times (600-x)-600\\\\96 = \frac{4x}{5} + 750 - \frac{5x}{4} - 600\\\\\frac{4x}{5} - \frac{5x}{4} = 96 - 750 + 600\\\\\frac{-9x}{20} = -54\\\\x = 54 \times \frac{20}{9}\\\\x = 120$

Thus the cost of the lower priced bangle set is Rs 120

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