Question

Deepika is twice as old as his brother vikash. If the difference of their age is 11. Find there age​

Answer 1

Let Vikash age = x

Then age of deepika = 2x

Difference of ages = 11

2x - x = 11

x = 11

Which implies deepikas age = 2*11 = 22

Answer 2

Answer :-

Deepika's age is 22 years and Vikash's age is 11

Explanation :-

Given :-

Deepika = twice of her brother Vikash

Difference of their ages = 11

To find :-

Deepika and Vikash's ages

Solution :-

Consider Vikash's age as x

Consider Deepika's age as 2x

The Equation :-

$\tt{\Rightarrow \: 2x - x = 11}$

$\tt{\Rightarrow \: x = 11}$

Vikash's age = 11 years

Deepika's age = $\tt{\2x}$

$\tt{\Rightarrow2 \times 11}$

$\tt{\Rightarrow22}$

Deepika's age = 22 years

Verification :-

Place the values of the numbers we found in the Equation.

LHS :

$\tt{\rightarrow(11 \times 2) - 11 }$

RHS :

$\tt{\rightarrow11}$

$\tt{\Rightarrow(11 \times 2) - 11 = 11 }$

$\tt{\Rightarrow22 - 11 = 11}$

$\tt{\Rightarrow11 = 11}$

RHS =LHS

$\therefore$ Deepika's age is 22 years and Vikash's age is 11