def is an isosceles triangle with de = df draw dp perpendicular ef to show that angle E=angle F
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which AB = AC. E is point on the side CB produced such that FE AC . If AD CB. Prove that : AE × EF = AD × EC. ... In the given figure , ABC is an isosceles triangle in which AB=AC. E is point on the ... To prove : AB×EF=AD×EC ... ∴∠B=∠C (angles opposite to equal sides are equal) - (1) ... ΔADB∼ΔECF.
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