∆ DEF is an Isosceles triangle with DE = EF. If ˪F = 500 , Find the measure of ˪D and ˪E.
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REF.image
To prove : AB×EF=AD×EC
⇒
EC
AB
=
EF
AD
Proof :
AB=AC (∵ ABC is isosceles)
∴∠B=∠C (angles opposite to equal sides are equal) - (1)
In ΔABD and ΔECF
∠ABD=∠ECF (from (1))
∠ADB=∠EFC (Both are 90
∘
)
Using AA similarity
ΔADB∼ΔECF
⇒
EC
AB
=
EF
AD
⇒AB×EF=AD×EC
∴ Hence proved.
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