Question

∆DEF ~ ∆MNK if de=2 mn =5 then find the value of A(∆DRF) A(∆MNK

Answer 1

Answer:

$2 {}^{2} \div 5 {}^{2} = \frac{4}{10}$

$4 \: is \: to \: 10$

Step-by-step explanation:

4:10 is the answer.

Ar(DRF)÷Ar(MNK)=4:10

Answer 2

Answer:

ratio of area of two similar triangles is equal to ratio of the square of their corresponding sides

ar triangle dEf/ar triangle mnk =(de/mn) ^2 =( 2/5)^2 =4/25

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