∆DEF ~∆MNK.if DE=5 AND MN=6
FIND A(∆DEF)/A(∆MNK)
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Answer:
Given ΔDEF∼ΔMNK and DE=5,MN=6
∴
A(ΔMNK)
A(ΔDEF)
=
MN
2
DE
2
(ratio of areas of similar triangles is equal to ratio of squares of the corresponding sides).
=
6
2
5
2
=
36
25
∴
A(ΔMNK)
A(ΔDEF)
=
36
25
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