Question

DEF= PQR, if angle DEF=75and angle QRP=80,then find angle FDE

Answer 1

180 - 75+80
180 - 155
25 ( is the answer for your question)


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Answer 2

here the triangles are congruent so corresponding parts are same so angle def = angle pqr = 75° ; angle QRP = angle EFD = 80° ; angle fde = angle rpq = 180°-(75°+80°)=25°