defferentiation of
(sin x - cos x)/(sin x + cos x)
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Answer:
(sinx-cosx)/(sinx+cosx)
=((sinx+cosx)(cosx+sinx)-(sinx-cosx)(cosx-sinx))/(sinx+cosx)^2
=((sinx+cosx)^2+(sinx-cosx)^2)/(sinx+cosx)^2
=2(sin^2+cos^2)/(sin^2+cos^2+2sinxcosx)
=2(1)/(1+sin2x)
=2/(1+sin2x)
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