Question

Define a function calles myfunc which takes a string and returns a matching strin where every even letter is in capital and odd letter in lower case

Answer 1

Answer:

def myfunc(word):

result = ""

index = 0

for letter in word:

if index % 2 == 0:

result += letter.lower()

else:

result += letter.upper()

return result

index +=1

Explanation:

Answer 2

Python code for the given problem statement is given below

Code:

#defining myfunc

def myfunc(string):

   new_str="" #initialising a new string

   for i in range(len(string)): #iterating over the given string

       if i%2 == 0: #checking whether divisible by 2

           #since it is even letter, capital letter is added to new string

           new_str+=string[i].upper()

       else: #if not divisible by 2

           #since it is odd letter, small letter is added to new string

           new_str+=string[i].lower()

   return new_str #returning the required string

#main function

string = input() #taking string input from user

print("Output is " +myfunc(string)) #print output of myfunc

Output:

Hello World

Output is HeLlO WoRlD

#SPJ3