Question

Define a function void Roots( double a, double b, double c ) to find the results of x1, x2 from the
following relation. Print the values of a, b, c and values of x1, x2 as output.
xl =
-b+ √b² - 4ac
2a
and x2 =
-b - √b² - 4ac
2a​

Answer 1

import java.util.Scanner;

import java.lang.Math;

public class main{

   public static void main(String[] str)

   {

       System.out.println("Enter 1st number: ");

       Scanner input = new Scanner(System.in);

       double num = input.nextDouble();

       

       System.out.println("Enter 2nd number: ");

       Scanner input2 = new Scanner(System.in);

       double num2 = input2.nextDouble();

       

       System.out.println("Enter 3rd number: ");

       Scanner input3 = new Scanner(System.in);

       double num3 = input3.nextDouble();

       

       System.out.println(root(num,num2,num3));

       System.out.println(root2(num,num2,num3));

   }

   public static double root (double a, double b ,double c)

   {

       double x1;

       x1 = -b + Math.sqrt(b*b) - 4*a*c + 2*a; // you didnot wrote any operator after -4ac, so I put + operator myself you can replace it with any valid operator

       return x1;

   }

   public static double root2 (double a, double b ,double c)

   {

       double x2;

       x2 = -b - Math.sqrt(b*b) - 4*a*c + 2*a; // you didnot wrote any operator after -4ac, so I put + operator myself you can replace it with any valid operator

       return x2;

   }

}