Question

Define acceleration due to gravity. What is the average value of acceleration due to gravity on the surface of the earth?

Answer 1

Answer:

roughly 9.8 m/s2

Explanation:

At the surface of the Earth, the acceleration due to gravity is roughly 9.8 m/s2 (32 ft/s2). The average distance to the centre of the Earth is 6,371 km (3,959 mi). , we can work out gravitational acceleration at a certain altitude.

The acceleration which is gained by an object because of gravitational force is called its acceleration due to gravity. Its SI unit is m/s2 . ... The acceleration due to gravity at the surface of Earth is represented by the letter g. It has a standard value defined as 9.80665 m/s2 (32.1740 ft/s2).

Answer 2

HEY MATE...!!!✌

➠ Acceleration Due to Gravity​

• Acceleration due to gravity is the acceleration gained by an object due to gravitational force.  
• The average value of g on the surface of the earth at sea level is 9.8 m/s².
• Its SI unit is m/s².  
• It has both magnitude and direction, hence, it’s a vector quantity.  
• Acceleration due to gravity is represented by g.  

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-: Additional Information :-

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➠ What is Gravity ?

• Gravity is the force with which earth attracts a body towards its centre.  
• Let us consider two bodies of masses ma and mb.  
• Under the application of equal forces on two bodies, the mass in terms of mass is given by :-

mb = ma [aA/aB] this is called an inertial mass of a body.

➠ Formula of Acceleration due to Gravity

• Force acting on a body due to gravity is given by, f = mg
• Where f is the force acting on the body, g is the acceleration due to gravity, m is mass of the body.
• According to the universal law of gravitation, f = GmM/(r+h)²

➠ Symbols and Full Forms

1. f = force between two bodies,
2. G = universal gravitational constant (6.67×10^-11 Nm²/kg²)
3. m = mass of the object,
4. M = mass of the earth,
5. r = radius of the earth.
6. h = height at which the body is from the surface of the earth.

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