define Angle differ from its complementary by 10 degree find the angles
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Answered by
3
Let angles are x and (x - 10),
Their sum = 90°
x + x - 10 = 90°
2x = 90 + 10
2x = 100
x = 50°
Angles are x=50° and 50°-10° = 40°
I hope this will help you
(-:
Their sum = 90°
x + x - 10 = 90°
2x = 90 + 10
2x = 100
x = 50°
Angles are x=50° and 50°-10° = 40°
I hope this will help you
(-:
Answered by
0
Heya !!!
Let angle be X°.
Other angle = ( X°-10)
As we know that sum of two complementary angles is 90°.
So,
X + X - 10 = 90
2X = 90+10
2X = 100
X = 100/2 = 50°
Angle = X° = 50°
Other angle = X° - 10 = 50°-10 = 40°
★ HOPE IT WILL HELP YOU ★
Let angle be X°.
Other angle = ( X°-10)
As we know that sum of two complementary angles is 90°.
So,
X + X - 10 = 90
2X = 90+10
2X = 100
X = 100/2 = 50°
Angle = X° = 50°
Other angle = X° - 10 = 50°-10 = 40°
★ HOPE IT WILL HELP YOU ★
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