define Avogadro's number and calculate the mass of 1.050 5 x 10 to the power 23 molecules of carbon dioxide
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1) avagadro no. states that 1 mole = 6.022×10^23 molecules.
2) G.M.M of carbon dioxide =12+ 16×2= 12+32 = 44g.
Now, G.M.M = 6.022×10^23 molecules
44g=6.022×10^23
44/6.022×10^23 = 1 molecule
44×1.0505×10^23/6.022×10^23 = 1.050×10^23
7.67g
in this first of all we will put gram molecular mass equal to avagadro no. then we will find the gram of 1 molecule and so as to find the mass of given molecules we will multiply it
2) G.M.M of carbon dioxide =12+ 16×2= 12+32 = 44g.
Now, G.M.M = 6.022×10^23 molecules
44g=6.022×10^23
44/6.022×10^23 = 1 molecule
44×1.0505×10^23/6.022×10^23 = 1.050×10^23
7.67g
in this first of all we will put gram molecular mass equal to avagadro no. then we will find the gram of 1 molecule and so as to find the mass of given molecules we will multiply it
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